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GB-23-03-001 · Equation of a straight line

Find the equation of the line with gradient 5 passing through (−2,−1)(-2,-1).

Coordinate Geometry: Equation of a Line Booklet p. 81
Method
1) Identify gradient and point
2) Substitute into y−y1=m(x−x1)y-y_1=m(x-x_1)
3) Clear any denominator before expanding
4) Rearrange
Worked Example (GB-23-03-001)
1)
Use the booklet's point-gradient formula: y−y1=m(x−x1)y-y_1=m(x-x_1).
2)
y−(−1)=5(x−(−2))y-(-1)=5(x-(-2))
3)
Expand: y+1=5x+10y + 1=5x + 10.
4)
Rearrange: y=5x+9y=5x + 9.
Ans = y=5x+9y=5x + 9